2x+3/5x+2 = 4x+5/10x+2
<=> (2x+3)(10x+2)=(5x+2)(4x+5)
<=>2x(10x+2)+3(10x+2)= 5x(4x+5)+2(4x+5)
<=> 20x^2+4x+20x+6 = 20x^2+25x+9x+10
<=> 20x^2+4x+20x+6 - (20x^2+25x+9x+10)=0 => 20x^2+24x+6-(20x^2+34x+10)=0
<=> -10x-4=0
<=>-10x=4
<=> x= -4/10
2x+3/5x+2=4x+5/10x+2
=> (2x+3)(10x+2)=(5x+2)(4x+5)
=> 20x^2+4x+30x+6=10x^2+25x+8x+10 ( Vì cả hai vế đều có 10x^2 nên ta xóa đi )
=> 34x+6=33x+10
=> 34x-33x=-6+10
=> x=4
2x+3/5x+2=4x+5/10x+2
<=>(2x+3)(10x+2)=(4x+5).(5x+2)
<=>2x.(10x+2)+3.(10x+2)=5x.(4x+5)+2.(4x+5)
<=>20x^2+4x+30x+6=20x^2+25x+8x+10
<=>4x+30x+6=20x^2+25x+8x+10-20x^2
<=>x.(4+30)+6=(20x^2-20x^2)+x.(25+8)+10
<=>34x+6=0+33x+10
<=>34x-33x=10-6
<=>x=4
Vậy x=4