ta có :
2^x+2^x+1+2^x+2=112
2^x(1+2^1+2^2)=112
2^x*7=112
2^x=16
suy ra x=4
\(2^x+2^{x+1}+2^{x+2}=112\)
=> \(2^x.1+2^x.2+2^x.2^2=112\)
=> \(2^x.\left(1+2+4\right)=112\)
=> \(2^x.7=112\)
=> \(2^x=112:7=16\)
=> \(2^x=2^4\)
=> \(x=4\)
Ta có: \(2^x+2^{x+1}+2^{x+2}=112\)
\(\Rightarrow2^x+2^x.2+2^x.2^2=112\)
\(\Rightarrow2^x\left(1+2+2^2\right)=112\)
\(\Rightarrow2^x.7=112\)
\(\Rightarrow2^x=16\)
Mả \(16=2^4\Rightarrow2^x=2^4\Rightarrow x=4\)
Vậy x = 4.