Theo đầu bài ta có:
\(\left(2x-7\right)^{24}+\left(7-2x\right)^{24}=2\)
\(\Rightarrow\left(2x-7\right)^{24}+\left[-\left(2x-7\right)\right]^{24}=2\)
\(\Rightarrow\left(2x-7\right)^{24}+\left(2x-7\right)^{24}=2\)
\(\Rightarrow\left(2x-7\right)^{24}\cdot2=2\)
\(\Rightarrow\left(2x-7\right)^{24}=1\)
\(\Rightarrow\orbr{\begin{cases}2x-7=1\\2x-7=-1\end{cases}\Rightarrow\orbr{\begin{cases}2x=8\\2x=6\end{cases}\Rightarrow}\orbr{\begin{cases}x=4\\x=3\end{cases}}}\)