\(\left(2x-3\right)^2=\frac{9}{4}=\left(\frac{-3}{2}\right)^2=\left(\frac{3}{2}\right)^2\)
\(\Leftrightarrow\orbr{\begin{cases}2x-3=\frac{-3}{2}\\2x-3=\frac{3}{2}\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=\frac{3}{4}\\x=\frac{9}{4}\end{cases}}\)
Vậy \(x=\frac{3}{4}\)hoặc \(x=\frac{9}{4}\)