Question

tìm x  biết :

2^x + 2^x+2 + 2^{x + 3} = 832

Answer 1

\(2^x+2^{x+2}+2^{x+3}=832\)

\(\Rightarrow2^x\left(1+2^2+2^3\right)=832\)

\(\Rightarrow2^x\cdot13=832\)

\(\Rightarrow2^x=64\)

\(\Leftrightarrow x=6\)

Answer 2

2^x + 2^x+2 + 2^x+3 = 832

=> 2^x + 2^x . 2² + 2^x + 2³ = 832

=> 2^x + 2^x . 4 + 2^x + 8 = 832

=> 2^x ( 1 + 4 + 8 ) = 832 

=> 2^x . 13 = 832 

=> 2^x = 64

=> 2^x = 2⁶

=> x = 6 

Vậy x = 6

Answer 3

\(2^x+2^{x+2}+2^{x+3}=832\)

\(\Rightarrow2^x\left(1+2^2+2^3\right)=832\)

\(\Rightarrow2^x.13=832\)

\(\Rightarrow2^x=832:13=64=2^6\)

\(\Rightarrow x=6\)

Answer 4

2^x + 2^x+2 + 2^x+3 = 832

=> 2^x +  2^x . 2² + 2^x . 2³ = 832

=> 2^x . ( 2² + 2³ + 1 ) = 832

=> 2^x . 13 = 832

=> 2^x = 64

=> 2^x = 2⁶ 

=> x = 6

Answer 5

2^x + 2^x+2 + 2^{x + 3} = 832

=>2^x+2^x.2²+2^x.2³=832   

=>2^x(1+2²+2³)=832

=>2^x.13=832

=>2^x=832:13

=>2^x=64

=>2^x=2⁶

=>x=6.Vậy x=6.                        

Answer 6

2^x + 2^x+2 + 2^x+3 = 832

<=> 2^x + 2^x .2² + 2^x .2³ =832

<=>2^x.(1+2²+2³)=832

<=>2^x.13=832

<=>2^x=64

<=>2^x=2⁶

=>x=6

vậy...

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