\(+2x\ge1\Rightarrow|2x-1|+|1-2x|=2x-1+2x-1=2\left(2x-1\right)=8\Leftrightarrow2x-1=4\Leftrightarrow x=2,5\)
\(+2x\le1\Rightarrow|2x-1|+|1-2x|=1-2x+1-2x=2\left(1-2x\right)\Leftrightarrow1-2x=4\Leftrightarrow x>1\left(loại\right)\)
\(Vậy:x=2,5\)
Bạn nào t i c k sai cho mk vậy nếu mk lm gì thì mk xin lỗi nha lần sau đừng t i c k sai cho mk nha mk xin bạn đó
\(\left|2x-1\right|+\left|1-2x\right|=\left|2x-1\right|+\left|2x-1\right|=2.\left|2x-1\right|=8\)
\(\Rightarrow\left|2x-1\right|=4\Rightarrow\orbr{\begin{cases}2x-1=4\\2x-1=-4\end{cases}\Rightarrow\orbr{\begin{cases}2x=5\\2x=-3\end{cases}\Rightarrow}\orbr{\begin{cases}x=\frac{5}{2}\\x=-\frac{3}{2}\end{cases}}}\)
Vậy \(x=\frac{5}{2}\)hay \(x=-\frac{3}{2}\)
