\(24\)+\(\frac{x}{50}\)+\(x\)=\(\frac{3}{5}\)
<=>\(\frac{1250}{50}\)+\(\frac{x}{50}\)+\(\frac{50x}{50}\)=\(\frac{30}{50}\)
<=>\(\frac{1250+x+50x}{50}\)=\(\frac{30}{50}\)
=>\(1250\)+\(x\)+\(50x\)=30
=>\(51x\)=\(30\)-\(1250\)
=>51x=-1220
=>x=\(\frac{-1220}{51}\)
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