Tìm x, biết:
\(\left(\frac{2}{3}\cdot x-\frac{1}{5}\right)^2=\frac{4}{9}\)
\(\Rightarrow\left(\frac{2}{3}\cdot x-\frac{1}{5}\right)^2=\left(\frac{2}{3}\right)^2=\left(-\frac{2}{3}\right)^2\)
\(\Rightarrow\orbr{\begin{cases}\frac{2}{3}\cdot x-\frac{1}{5}=\frac{2}{3}\\\frac{2}{3}\cdot x-\frac{1}{5}=-\frac{2}{3}\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}\frac{2}{3}\cdot x=\frac{13}{15}\\\frac{2}{3}\cdot x=-\frac{7}{15}\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{13}{10}\\x=-\frac{7}{10}\end{cases}}\)