dat a =2009-x
b=x-2010
ta co : a^2+ab+b^2/a^2-ab+b^2 =19/49
<=>49a^2+49ab+49b^2=19a^2-19a+19b^2
<=>30a^2+68a+30b^2=0
<=>15a^2+34ab+15b^2=0
<=>15a^2+9ab+25ab+15b^2=0
<=>3a(5a+3b)+5b(5a+3b)=0
<=>(5a+3b)(3a+5b)=0
<=>5a+3b=0 hoac 3a+5b=0
vs 5a +3b=0 <=>5(2009-x)+3(x-2010)=0=>x=......
tìm x biết :
(2009 - x^2) + ( 2009 - x^2)( x - 2010) + ( x - 2010) / (2009 - x^2) - ( 2009 - x^2)( x - 2010) + ( x - 2010 ) = 19/49
Tìm x biết: (2009-x)2 + (2009-x)(x-2010) + (x-2010)2/(2009-x)2 - (2009-x)(x-2010) + (x-2010)2 = 19/49
Tìm x : (2009-x)2+(2009-x)(x-2010)+(x-2010)2/(2009-x)2-(2009-x)(x-2010)+(x-2010)2=19/49
TÌM X
{[2009-x]^2+[2009-x][x-2010]+[x-2010]^2}/{[2009-x]^2-[2009-x][x-2010]+[x-2010]^2}=19/49
tim x
(2009-x)^2+(2009-x)×(x-2010)+(x-2010)^2/(2009)^2-(2009-x)×(x-2010)+(x-2010)^2=19/49
(2009-x)2+(2009-x)(2010-x)+(2010-x)2/(2009-x)2+(2009-x)(2010-x)+(2010-x)2 = 19/49
tìm x
tìm x biết \(\frac{\left(2009-x\right)^2+\left(2009-x\right)\left(x-2010\right)+\left(x-2010\right)^2}{\left(2009-x\right)^2-\left(2009-x\right)\left(x-2010\right)+\left(x-2010\right)^2}=\frac{19}{49}\)
Tìm x biết:
\(\frac{\left(2009-x\right)^2+\left(2009-x\right)\left(x-2010\right)+\left(x-2010\right)^2}{\left(2009-x\right)^2-\left(2009-x\right)\left(x-2010\right)+\left(x-2010\right)^2}=\frac{19}{49}\)
(2009-x)2+(2009-x)(x-2010)+(x-2010)2/(2009-x)2-(2009-x)(x-2010)+(x-2010)2=19/49
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