\(\left(1-2x\right)3=27\)
\(3-6x=27\)
\(6x=3-27\)
\(6x=-24\)
\(x=-24:6\)
\(x=-4\)
( 1 - 2x ) x 3 = 27
( 1 - 2x ) = 27 : 3
( 1 - 2x ) = 9
<=> 1 - 2x = 9
<=> 2x = ( 9 + 1 )
<=> 2x = 10
<=> x = 10 : 2 = 5
=> x = 5
\(\left(1-2x\right)3=27\)
<=>\(1-2x=\frac{27}{3}\)
<=> \(1-2x=9\)
<=>\(-2x=9-1\)
<=>\(-2x=-8\)
<=>\(x=\frac{-8}{-2}\)
<=>\(x=4\)
Vậy \(x=4\)