Ta có:\(\frac{12-3x}{32}=\frac{6}{4-x}\)
\(\Leftrightarrow\left(12-3x\right)\left(4-x\right)=32.6\)
\(\Leftrightarrow3\left(4-x\right)\left(4-x\right)=192\)
\(\Leftrightarrow\left(4-x\right)^2=64\)
\(\Leftrightarrow\orbr{\begin{cases}4-x=8\\4-x=-8\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=12\\x=-4\end{cases}}\)
Vậy x = 12 hoặc x = -4
Linz
\(\frac{12-3x}{32}=\frac{6}{4-x}\)
\(\Leftrightarrow\left(12-3x\right)\left(4-x\right)=192\)
\(\Leftrightarrow3\left(4-x\right)\left(4-x\right)=192\)
\(\Leftrightarrow\left(4-x\right)^2=64\)
\(\Rightarrow\orbr{\begin{cases}4-x=8\\4-x=-8\end{cases}\Rightarrow\orbr{\begin{cases}x=-4\\x=12\end{cases}}}\)
\(\frac{12-3x}{32}=\frac{6}{4-x}\left(đkxđ:x\ne4\right)\)
\(< =>\left(12-3x\right)\left(4-x\right)=32.6\)
\(< =>3\left(4-x\right)\left(4-x\right)=32.6\)
\(< =>\left(4-x\right)^2=\frac{32.6}{3}=32.2=64\)
\(< =>\orbr{\begin{cases}4-x=8\\4-x=-8\end{cases}< =>\orbr{\begin{cases}x=-4\\x=12\end{cases}}}\)
Kho the sao em lam duoc em moi hoc lop 4 a kkkk toi chi hay anh gap nguoi ngu nhu em
