1/1.4 + 1/4.7 + 1/7.10 + ... + 1/97.100=0,33.x/2009
[1/1.4+1/4.7+1/7.10+...+1/97.100=0,33.x/2009
tìm x :
(1/1.4+1/4.7+1/7.10+...+1/97.100)=0,33.x/2009
giúp mình nhé mình đang cần gấp.
Tìm x biết:
\(\left(\frac{1}{1.4}+\frac{1}{4.7}+\frac{1}{7.10}+...+\frac{1}{97.100}\right)=\frac{0,33.x}{2009}\)
Tìm x, biết:
a) 2x+ 2x+1 + 2x+2+ 2x+3 = 480
b) \(\frac{1}{1.4}+\frac{1}{4.7}+\frac{1}{7.10}+..................+\frac{1}{97.100}=\frac{0,33.x}{2009}\)
mk đang cần gấp
(\(\frac{1}{1.4}+\frac{1}{4.7}+\frac{1}{7.10}+..........+\frac{1}{97.100}=\frac{0.33.x}{2009}\))
\(\frac{1}{1.4}+\frac{1}{4.7}+\frac{1}{7.10}+........+\frac{1}{97.100}=\frac{0.33..x}{2009}\)
giúp mik nhé
Tìm X <- N biết
b) ( \(\frac{11}{1.3}\)+ \(\frac{11}{3.5}\)+ ......... + \(\frac{11}{97.99}\)) . 2x = \(\frac{49}{9}\)
c) \(\frac{1}{1.4}\)+ \(\frac{1}{4.7}\)+ \(\frac{1}{7.10}\) + ........+ \(\frac{1}{97.100}\)= \(\frac{0,33.x}{2009}\)
A=1/2+ 1/6+1/12+...+1/132
B= 5/1.4+ 5/4.7+5/7.10+...+5/97.100