tim x biet : (11/12+11/12.23+11/23.24+...+11/89.100) + x = 2/3
giup minh voi minh dang can gap xin cam on nhieu
Tìm x:
A)11/12+11/12.23+11/23.24+....+11/89.100+x=2/3
B)2/11.13+2/13.15+...+2/19.21-x+221/223=4/3
tìm x biết:
a, (11/12+11/12.23+11/23.24+...+11/89.100)+x=2/3
b, (2/11.13+2/13.15)+...+2/19.21)-x+221/231=4/3
Giúp mk nha ai giải đc mk tick cho nhé!
(\(\frac{11}{12}+\frac{11}{12.23}+\frac{11}{23.24}+...+\frac{11}{89.100}\))+x = \(\frac{2}{3}\)
\(\frac{11}{12}+\frac{11}{12.23}+\frac{11}{23.24}+...+\frac{11}{89.100}\)=?
tìm x, biết
a, \(\left(\frac{11}{12}+\frac{11}{12.23}+\frac{11}{23.24}+...+\frac{11}{89.100}\right)+x=\frac{5}{3}\)
b, \(\left(\frac{2}{11.13}+\frac{2}{13.15}+...+\frac{2}{19.21}\right)-x+4+\frac{221}{231}=\frac{7}{3}\)
11/12+11/12.23+11/23.34+...+11/89.100+x=2/3
(11/12 + 11/12.23 + 11/23.34 + ... + 11/89.100) + x = 1va 2/3
\(\left(\frac{11}{12}+\frac{11}{12.23}+\frac{11}{13.24}+...+\frac{11}{89.100}\right)+x=\frac{2}{3}\)