Các câu hỏi tương tự
Tìm x biết 1/1 +1/3 + 1/6 + ... + 2/x.(x+1) = 1\(\frac{2008}{2010}\)
Tìm x biết 1/1+1/3+1/6+...+2/x(x+1)= \(1\frac{2008}{2010}\)
Tìm x, biết:
\(\left(1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{2008}\right).x=\frac{2009}{1}+\frac{2010}{2}+\frac{2011}{3}+...+\frac{4016}{2008}-2008\)
tìm STN x biết:1/3+1/6+1/10+...+2/x.(x+1)=2008/2010
tìm STN x biết:1/3+1/6+1/10+...+2/x.(x+1)=2008/2010
Bài 2: Tìm x: (2đ)
b; \(\frac{1}{1} +\frac{1}{3}+\frac{1}{6} +...+\frac{2}{x.\left(x+1\right)}=1\frac{2008}{2010}\)
3. Tìm x biết :
\(\frac{x-1}{2011}+\frac{x-2}{2010}+\frac{x-3}{2009}=\frac{x-4}{2008}\)
2. Tìm x nguyên biết :
\(1-3+3^2-3^3+...+\left(-3\right)^x=\frac{9^{1006}-1}{4}\)
1+\(\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+....+\frac{2}{x.\left(x+1\right)}=1\frac{2008}{2010}\)
a, \(\dfrac{5}{2}-3\left(\dfrac{1}{3}-x\right)=\dfrac{1}{4}-7x\)
b, \(\left(1+\dfrac{1}{2}+\dfrac{1}{3}+...+\dfrac{1}{2008}\right).x=\dfrac{2009}{1}+\dfrac{2010}{2}+...+\dfrac{5016}{2008}-2008\)
c, \(\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+...+\frac{2}{x.\left(x+1\right)}=\frac{2001}{2003}\)
GIÚP VỚI , MIK CẦN GẤP