\(102:\left[2012-\left(x-12\right)\right]=6\)
\(102:\left[2012-x+12\right]=6\)
\(102:\left(2024-x\right)=6\)
\(2024-x=102:6\)
\(2024-x=17\)
\(x=2007\)
Ta có \(102\div\left(2012-\left(x-12\right)\right)=6\)
\(\Rightarrow2012-\left(x-12\right)=102\div6\)
\(\Rightarrow2012-\left(x-12\right)=17\)
\(\Rightarrow x-12=2012-17\)
\(\Rightarrow x-12=1995\)
\(\Rightarrow x=1995+12\)
\(\Rightarrow x=2007\)
A.\(102\div\left(2012\left(x-12\right)\right)=6\)
\(2012-\left(x-12\right)=\frac{102}{6}=17\)
\(x-12=2012-17=1995\)
\(x=1995+12=2007\)
Vậy x=2007
2012-(x-12) = 102 : 6
x-12 = 2012-17
x = 1995+12
102 : (2012 - (x - 12) = 6
2012 - (x - 12) = 102 : 6 = 17
x - 12 = 2012 - 17 = 1995
x = 1995 + 12 = 2007
102 : ( 2012 - ( x - 12 ) = 6
2012 - ( x - 12 ) = 102 : 6 = 17
x - 12 = 2012 - 17 = 1995
x = 1995 + 12
x = 2007
~~~học tốt nha~~~
