= (x2+1)3 - [(x2)3 + 13]=0
(x6+ 3.x4 +3.x2 +1) - (x6+1) =0
x6+3.x4+3.x2+1-x6-1=0
3.x4+3.x2=0
3.x2(x2+1)=0
\(\orbr{\begin{cases}3.x^2=0\\x^2+1=0\end{cases}}\orbr{ }\Rightarrow\orbr{\begin{cases}x=0\\x^2=-1\left(loai\right)\end{cases}}\)
vay x=0
Tìm x biết :
a, 4.(18 - 5x) - 12.(3x - 7) = 15.(2x - 16) - 6(x + 14)
b, 5.(3x + 5) - 4.(2x - 3) = 5x + 3.(2x + 12) + 1
c, 2.(5x - 8) - 3.(4x - 5) = 4.(3x - 4) + 11
d, (3x + 2)(2x + 9) - (x + 2)(6x + 1) = (x + 1) - (x - 6)
e, (8x - 3)(3x + 2) - (4x + 7)(x + 4)= (2x + 1)(5x - 1) - 33
a) 1/x-1 + -2/3 x (3/4 - 6/5) = 5/2-2x
b) 3 - 2/2x-3 = 2/5 + 2/9-6x - 3/2
c) x/2 - 1/x = 1/12
: Tìm x, biết:
a) 3x( 4x- 1) - 2x(6x- 3 )=30 b) 2x(3-2x) + 2x(2x-1)=15
c) (5x-2)(4x-1) + (10x +3)(2x - 1)=1 d) (x+2) (x+2)- (x -3)(x+1) = 9
e) (4x+1)(6x-3) = 7 + (3x – 2)(8x + 9) g) (10x+2)(4x- 1)- (8x -3)(5x+2) =14
Tìm x biết: ( x + 3 )3 - x(3x + 1)2+ (2x + 1)(4x2 - 2x +1 )- 3x = 54
( x- 3 )3 - ( x - 3 ) ( x2 + 3x + 9 ) + 6 ( x + 1 )2 + 6x2 = -33
Tìm x , mấy bạn giúp vs ạ .E có quàa
1 , | x - 9 | - x = 15 - ( -2) + |- 17|
2 , | 2x^2 + 1 | - 3x = 2x^2 - x + 5
3 , 3 - 5 . | x+1| = 24
4 , | 3-x | - 2x = 4
5 , | x+3| + | x-3 | + | x+6| = 6x - 18
6 , | x+2| + |x+3| = x
7 , | x-1| + |y-1| = 0
a,-2(x-1/2)-5(3/10-x)=7
b,-2/3(3/2-x)=3/4(1/6x-2/9)
c,4-2/3(x-3)=2x-1/2+2/3
tìm x biết
(x+2)(x+3)-(x-2)(x+5)=6;
(3x+2)(2x+9)-(x+2)(6x+1)
bài 1: tính
a) -6x+3(7+2x)
b)15y-5(6x+3y)
c) x(2x+1)-x2(x+2)+(x3-x+3)
d)4(x-6)-x2(2+3x)+x(5x-4)3x2(x-1)
bài 2: tìm x
a)3x+2(5-x)=0
b)3x2-3x(-2+x)=36
c)5x(12x+7)-3x(20x-5)=-100
1.Tìm x trong tỉ lệ thức
(1/3x):2/3=1 và 3/4 : 2/5
0,2:1 và 1/5 = 2/3 : (6x + 7 )
x-1/-15=-60/x-1
x-1/7=9/x-1
x-3/5-x=5/7
x-1/x+2=x-2/x+3
