a) \(3^x+6=9\Rightarrow3^x=3\Rightarrow3^x=3^1\Rightarrow x=1\)
b) \(x-3=\frac{-1}{2}\Rightarrow x=\frac{-1}{2}+3\Rightarrow x=\frac{5}{2}\)
c) \(\left|3-x\right|=\frac{1}{2}\Rightarrow\orbr{\begin{cases}3-x=\frac{1}{2}\\3-x=\frac{-1}{2}\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{5}{2}\\x=\frac{7}{2}\end{cases}}\)
d) \(\left|x-2\right|+1=\frac{6}{4}\Rightarrow\left|x-2\right|=\frac{3}{2}-1\Rightarrow\left|x-2\right|=\frac{1}{2}\Rightarrow\orbr{\begin{cases}x-2=\frac{1}{2}\\x-2=\frac{-1}{2}\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{5}{2}\\x=\frac{3}{2}\end{cases}}\)
a.x=1
b.x=5/2
c.x=35/12;x=37/12
d.x=5;x=3/2
Chúc bạn học tốt!
Bạn viết rõ ra được k
Mình sửa ý c) nhé, nhầm đề bạn thông cảm.
\(\left|3-x\right|=\frac{1}{12}\Rightarrow\orbr{\begin{cases}3-x=\frac{1}{12}\\3-x=\frac{-1}{12}\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{35}{12}\\x=\frac{37}{12}\end{cases}}\)
