Question

Tìm x                                 a) 2/x = x/8.                    b) x+1/3 = x-2/4.   

Answer 1

a) \(\frac{2}{x}=\frac{x}{8}\Rightarrow x^2=2\cdot8=16\)

\(\Rightarrow\) x = 4 hoặc x = - 4

b) \(\frac{x+1}{3}=\frac{x-2}{4}\Rightarrow4\left(x+1\right)=3\left(x-2\right)\)

\(\Rightarrow4x+4=3x-6\)

\(\Rightarrow4x-3x=-6-4\)

\(\Rightarrow x=-10\)

Answer 2

A) 2/x =x/8 => 2x=16 => x=4 

B) x+1/3=x-2/4 =>4(x+1)=3(x-2)