Ta có: 5[x-2] + 3.[x+2] = 2-x
=> 5.x - 5.2 + 3.x + 3.2 = 2-x
=>5.x - 10 + 3.x +6 =2-x
=>[5.x-3.x] -[10-6] =2-x
=>2x - 4=2-x
=>2x+x =2+4=6
=>3x=6
=>x=6:3=2
Vậy x=2
Nhớ tick cho mình nha.
Ta có: 5[x-2] + 3.[x+2] = 2-x
=> 5.x - 5.2 + 3.x + 3.2 = 2-x
=>5.x - 10 + 3.x +6 =2-x
=>[5.x-3.x] -[10-6] =2-x
=>2x - 4=2-x
=>2x+x =2+4=6
=>3x=6
=>x=6:3=2
Vậy x=2
Nhớ tick cho mình nha.
Tim x biet : 20 . 2^x + 1 = 10.4^2 + 1
Tim x : ( 4-x:2)^3 - 1 = 2 . (2^3 - 5 : 2^0 )
1 )Tim x, y thuoc Z
x + y = x.y
2) Tim x thuoc Z
(x + 1)+(x+3)+(x+5)+...+(x+99)=0(x-3)+(x-2)+(x-1)+...+10+11=11-12(x-5)+7(3-x)=530(x+2)-6(x-5)-24x=100Tim x
x-3/ x-5=[-3/5] 2
x-2/3=3-2x/22
tim x
36: [ 7 x (X-3) + 4 ] =2^4 : 2^3
[(6 X - 39 ) :3 ] x 28 = 5628
720x [41 - (2 X - 5 =2^3 x 5
1.Tim cac chu so x va y de so 1x8y2 chia het cho 36
2.tim cac gia tri nguyen cua n de phan so A=3.n+2/n-1 co gia tri la so nguyen
3.tim cac chu so x y thoa man
(x-2)^2.(x-3)^2=4
4.tim so tu nhien x biet
(x-5):3/100=20.x/100 +5
2^x+1*2^2014=2^2015 tim x
7x-x=5^21/5^19+3*2^2-7 tìm x
Tim x biet
A 3/2.x-2/5=1/3.x-1/4
B -51/2.x+1=3/4-7/6
C 2.x-2/3=7.x+3/2-1
D 3/2.x-2/5=1/3.x -1/4
Tim x :
5/2 . x + 2/3 = 9/2.x
Bai 1: Tim so nguyen x biet:
x+(x+1)+(x+2)+...+35=0
Bai 2: Tim GTLN:
a) 8-(x+2)^2=E
b) -|x+2|+10=F
Bai 3: Tim x \(\in\)Z:
a)(2x-4)(x+4)<0
b)(x+5)(3x-12)>0
Bai 11: Cho:
S=1-2+3-4+5-6+...+19-20
a) S co\(⋮\)2; 3; 5 khong?
b) Tim tat ca cac uoc cua S
chi tiet gi minh nha