\(5\left(x-7\right)+2018^0=26\)
\(5x-35+1=26\)
\(5x-35=25\)
\(5x=60\)
\(x=12\)
\(5\left(x-7\right)+2018^0=26\)
\(\Rightarrow\left(5x-35\right)+1=26\)
\(\Rightarrow5x-35=25\)
\(\Rightarrow5x=60\)
\(\Rightarrow x=12\)
Vậy x = 12
\(5\left(x-7\right)+2018^0=26\)
\(5x-35+1=26\)
\(5x-35=26-1\)
\(5x-35=25\)
\(5x=25+35\)
\(5x=60\)
\(x=60:5\)
\(x=12\)
Vậy \(x=12\)
\(5\left(x-7\right)+2018^0=26\)
\(5x-35+1=26\)
\(5x-35=25\)
\(5x=60\)
\(x=12\)
Vậy x = 12
