\(5^{2x-3}-50=75\)
\(5^{2x-3}=75+50\)
\(5^{2x-3}=125\)
ta co: 125=5.5.5
nên\(2x-3=3\)
\(2x=6\)
x=3
52x-3 – 2.52 = 52.3
\(\Rightarrow\)52x-3-50=75
52x-3=75+50
52x-3=125
52x-3=53
\(\Rightarrow\)2.x-3=3
2.x=3+3
2.x=6
x=6:2
x=3
\(5^{2x-3}-2.5^2=5^2.3\)
\(5^{2x-3}\) \(=5^2.3+2.5^2\)
\(5^{2x-3}\) \(=75+50\)
\(5^{2x-3}\) \(=125\)
\(5^{2x-3}\) \(=5^3\)
\(2x-3\) \(=3\)
\(2x\) \(=3+3\)
\(2x\) \(=6\)
\(x\) \(=\)\(6:2\)
\(x\) \(=3\)
52x-3 - 2 . 5 2 = 5 2 . 3
52x -3 = 52.3+ 52 .2
52x -3 = 52 . ( 3+2 )
52x -3 = 52 . 5
52x -3 = 53
2x-3 = 3
2x = 3+3
2x = 6
x = 6 : 2
x = 3
Vậy x = 3
