=> (2x - 1)2 = 0
=> 2x - 1 =0
=> 2x = 1
=> x = 1/2
Đúng 0
Bình luận (0)
=> (2x - 1)2 = 0
=> 2x - 1 =0
=> 2x = 1
=> x = 1/2
Tìm x
x^2 - 4x - 12 = 0
4x^2 + 4x - 24 = 0
8x^3 - 12x^2 + 6x - 1 = 0
tìm x
4x(3 - 1/4x) + (x – 2)(x + 2) = 0
(2x+1)^2-4x^2+4x-1=0
tìm xTìm x : a) x^3 - 1/4x = 0 b) ( 2x - 1 )^2 - ( x + 3 )^2=0 c) x^2(x-3)+12-4x=0
tìm x biết
a)4x^2+4x-3=0
b)x^4-3x^3-x+3=0
c)x^2(x-1)-4x^2+8x-4=0
tìm x biết
a)4x^2+4x-3=0
b)x^4-3x^3-x+3=0
c)x^2(x-1)-4x^2+8x-4=0
Tìm x
a) 4x(x+1)-x-1 = 0
b) x3-4x2+4x =0
c) x2-3x + 2 =0
Tìm x
x^2 - 4x = 0
4x^2 - 9 = 0
2x ( x - 3 ) + 5( x - 3 ) = 0
x ( 2x + 9 )- 4x - 18
( 2x - 1 )^2 - ( x + 2 )^2 = 0
Tìm x
X mũ 2 +x+1/4=0
-x-2x+5=0
-4x mũ+4x-3=0