\(-4\left(x-1\right)^2+\left(2x-1\right)\left(2x+1\right)=-3\) \(3\)
<=> \(-4\left(x^2-2x+1\right)+4x^2-1=-3\)
<=> \(-4x^2+8x-4+4x^2-1=-3\)
<=> \(8x-5=-3\)
<=> \(8x=2\)
<=> \(x=\frac{1}{4}\)
\(-4\left(x-1\right)^2+\left(2x-1\right)\left(2x+1\right)=-3\)
\(\Rightarrow-4\left(x^2-2x+1\right)+4x^2-1=-3\)
\(\Rightarrow-4x^2+8x-4+4x^2-1=-3\)
\(\Rightarrow8x-5=-3\)
\(\Rightarrow8x=2\Rightarrow x=0,25\)
Vậy \(x=0,25\)
Chúc bạn học tốt.
\(-4\left(x-1\right)^2+\left(2x-1\right)\left(2x+1\right)=-3\)
\(\Rightarrow-4\left(x^2-2x+1\right)+4x^2-1=-3\)
\(\Rightarrow-4x^2+8x-4+4x^2-1=-3\)
\(\Rightarrow8x-5=-3\)
\(\Rightarrow8x=2\Rightarrow x=0,25\)
\(\Rightarrow x=0,25\)
Vậy \(x=0,25\)
Code : Breacker