Question

Tìm x :

\(3^{x-1}\)+ 5 . \(3^{x-1}\)= 162

Answer 1

\(3^{x-1}+5.3^{x-1}=162\)

\(3^{x-1}.\left(1+5\right)=162\)

\(3^{x-1}.6=162\)

3^x-1=162:6

3^x-1=27

3^x-1=3³

x-1=3

x=3+1

x=4

Answer 2

3^x-1+5.3^x-1=162

3^x-1.(1+5)=162

3^x-1.6=162

3^x-1=162:6

3^x-1=27

3^x-1=3³

=>x-1=3=>x=3+1=4