Question

tìm x: 3.(1/2-x)+1/3=7/6 -x

Answer 1

\(3.\left(\frac{1}{2}-x\right)+\frac{1}{3}=\frac{7}{6}-x\)

\(\frac{3}{2}-3x+\frac{1}{3}=\frac{7}{6}-x\)

\(\frac{11}{6}-3x=\frac{7}{6}-x\)

\(\frac{11}{6}-\frac{7}{6}=3x-x\)

\(\frac{4}{6}=2x\)

\(x=\frac{4}{6}:2\)

\(x=\frac{1}{3}\)

Answer 2

\(3.\left(\frac{1}{2}-x\right)+\frac{1}{3}=\frac{7}{6}-x\)

\(\Leftrightarrow\frac{3}{2}-3x+\frac{1}{3}=\frac{7}{6}-x\)

\(\Leftrightarrow-3x+x=\frac{7}{6}-\frac{3}{2}-\frac{1}{3}\)

\(\Leftrightarrow x\left(-3+1\right)=\frac{-2}{3}\)

\(\Leftrightarrow x.\left(-2\right)=\frac{-2}{3}\)

\(\Leftrightarrow x=\frac{-2}{3}:\left(-2\right)\)

\(\Leftrightarrow x=\frac{1}{3}\)

Answer 3

3.(12 −x)+13 =76 −x

32 −3x+13 =76 −x

116 −3x=76 −x

116 −76 =3x−x

46 =2x

x=46 :2

x=13 

Answer 4

        \(3\left(\frac{1}{2}-x\right)+\frac{1}{3}=\frac{7}{6}-x\)

\(\Leftrightarrow\frac{3}{2}-3x+\frac{1}{3}=\frac{7}{6}-x\)

\(\Leftrightarrow-3x+x=\frac{7}{6}-\frac{3}{2}-\frac{1}{3}\)

\(\Leftrightarrow-2x=-\frac{2}{3}\)

\(\Leftrightarrow x=\frac{1}{3}\)