ta có : 3.{3-[3-(3-x)]} =0
3. [ 3- (3 -3 +x )] =0
3. ( 3 - x ) =0
3 - x = 0
x = 3
vậy x = 3
=> 3-[3-(3-x)]=0
=> 3-(3-x)=3-0=3
=>3-x=3-3
=> 3-x=0
=>x=3-0=3
3.{ 3 - [ 3 - ( 3 - x ) ] } = 0
3.[ 3 - ( 3 - 3 + x ) ] = 0
3. ( 3 - 3 + 3 - x ) = 0
3 . ( 3 - x ) = 0
9 - 3x = 0
x = 3
Vậy x = 3
3.{3-[3-(3-x)]}=0
3-[3-(3-x)]=0:3
3-(3-x)=3-0
3-x=3-3
x=3-0
x=3