Question

Tìm x:  \(2^5\).x+\(3^3\).x=121-15.5

Answer 1

Ta có:

\(2^5.x+3^3.x=121-15.5\)

<=> 32x + 27x = 121 - 75

<=> x(32+27) = 46

<=> 59x=46

<=> x = \(\frac{46}{59}\)

Answer 2

\(x\left(2^5+3^3\right)=121-75=46\)

\(x\left(32+27\right)=x.59=46\)

=> \(x=\frac{46}{59}\)

Answer 3

2⁵.x+3³.x=121-15.5

x.(2⁵+3³)=121-75

x.(32+27)=46

x.59        =46

x          =46:59

x          =46/59