1)GT => (156-5x)/32=3
=> 156-5x=96
=> 5x=60
=> x=12
Tìm x :
( 156 - 5 . x ) : 32 + 130 = 133
( 156 - 5 . x ) : 32 = 133 - 130
( 156 - 5 . x ) : 32 = 3
156 - 5 . x = 3 × 32
156 - 5 . x = 96
5 . x = 156 - 96
5 . x = 60
x = 60 : 5
x = 12
Vậy x = 12
60 - [ (195 - 7 . x) : 5 + 2] . 3 = 0
=>[ (195 - 7 . x) : 5 + 2] . 3=60
=>(195 - 7 . x) : 5 + 2 =60:3=20
=>(195 - 7 . x) : 5=18
=>195 - 7 . x=90
=>7x=105
=>x=15
\(\left(156-5x\right):32+130=133.\)
\(\left(156-5x\right):32=133-130\)
\(\left(156-5x\right):32=3\)
\(\left(156-5x\right)=3\times32\)
\(156-5x=96\)
\(5x=156-96\)
\(5x=60\)
\(x=\frac{60}{5}=12\)
\(60-\left[\left(195-7x\right):5+2\right]\times3=0\)
\(\left[\left(195-7x\right):5+2\right]\times3=60-0\)
\(\left[\left(195-7x\right):5+2\right]\times3=60\)
\(\left[\left(195-7x\right):5+2\right]=60:3\)
\(\left(195-7x\right):5+2=20\)
\(\left(195-7x\right):5=20-2\)
\(\left(195-7x\right):5=18\)
\(195-7x=18\times5\)
\(195-7x=90\)
\(7x=195-90\)
\(7x=105\)
\(x=105:7\)
\(x=15\)
\(\)
\(\left(156-5x\right):32+130=133\)
\(\left(156-5x\right):32=133-130\)
\(\left(156-5x\right):32=3\)
\(\left(156-5x\right)=3.32\)
\(156-5x=96\)
\(5x=156-96\)
\(5x=60\)
\(x=60:5\)
\(x=12\)
\(60-\left[\left(195-7x\right):5+2\right].3=0\)
\(\left[\left(195-7x\right):5+2\right].3=60-0\)
\(\left[\left(195-7x\right):5+2\right].3=60\)
\(\left(195-7x\right):5+2=60:3\)
\(\left(195-7x\right):5+2=20\)
\(\left(195-7x\right):5=20-2\)
\(\left(195-7x\right):5=18\)
\(195-7x=18.5\)
\(195-7x=90\)
\(7x=195-90\)
\(7x=105\)
\(x=105:7\)
\(x=15\)
\(\left(156-5x\right)\div32+130=133\)
\(\left(156-5x\right)\div32=133-130\)
\(\left(156-5x\right)\div32=3\)
\(156-5x=3\times32\)
\(156-5x=96\)
\(5x=156-96\)
\(5x=60\)
\(x=60\div5\)
\(x=12\)
\(60-\left(195-7x\right)\div5+2)\times3=0\)
\(\left(195-7x\right)\div5+2)\times3=60-0\)
\(\left(195-7x\right)\div5-2)\times3=60\)
\(\left(195-7x\right)\div5+2=60\div3\)
\(\left(195-7x\right)\div5+2=20\)
\(\left(195-7x\right)\div5=20-2\)
\(\left(195-7x\right)\div5=18\)
\(195-7x=18\times5\)
\(195-7x=90\)
\(7x=195-90\)
\(7x=105\)
\(x=105\div7\)
\(x=15\)
