\(\frac{2x-y}{x+y}=\frac{2}{3}\Rightarrow2\left(x+y\right)=3\left(2x-y\right)\)
\(\Rightarrow6x-3y=2x+2y\)
\(\Rightarrow6x-2x=2y+3y\)
\(\Rightarrow\frac{x}{y}=\frac{5}{4}\)
Ta có: \(\frac{2x-y}{x+y}=\frac{2}{3}\)
\(\Rightarrow3.\left(2x-y\right)=2.\left(x+y\right)\)
\(\Rightarrow6x-3y=2x+2y\)
\(\Rightarrow6x-2x=3y+2y\)
\(\Rightarrow4x=5y\)
\(\Rightarrow\frac{x}{y}=\frac{5}{4}\)
Vậy tỉ số \(\frac{x}{y}=\frac{5}{4}\)
\(\frac{2x-y}{x+y}=\frac{2}{3}\)
=> 3 ( 2x - y ) = 2 ( x + y )
6 x - 3 y = 2 x + 2 y
6 x - 2 x = 2 y + 3 y
4 x = 5 y
=> \(\frac{x}{y}=\frac{5}{4}\)
ta có:
\(\frac{2x-y}{x+y}=\frac{2}{3}\Rightarrow2\left(x+y\right)=3.\left(2x-y\right)\)
\(\Rightarrow6x-3y=2x+2y\)
\(\Rightarrow6x-2x=2y+3y\)
\(\Rightarrow\frac{x}{y}=\frac{4}{5}\)
~~ học tốt nha ~~
Theo bài ra ta có:
\(\frac{2x-y}{x+y}=\frac{2}{3}\)
\(\Rightarrow2\left(x+y\right)=3\left(2x-y\right)\)( nhân chéo cả 2 vế )
\(\Rightarrow6x-3y=2x+2y\)
\(\Rightarrow6x-2y=2x+3y\)
\(\Rightarrow\frac{x}{y}=\frac{5}{4}\)
# Hok_tốt nha
\(\frac{2x-y}{x+y}=\frac{2}{3}\Leftrightarrow6x-3y=2x+2y\Leftrightarrow4x=5y\)
Vậy \(\frac{x}{5}=\frac{y}{4}\)
thấy đề chó nóng là đéo ổn r 🤣
\(\frac{2x-y}{x+y}=\frac{2}{3}\)
\(\Leftrightarrow3\left(2x-y\right)=2\left(x+y\right)\)
\(\Leftrightarrow6x-3y=2x+2y\)
\(\Leftrightarrow6x-2x=3y+2y\)
\(\Leftrightarrow4x=5y\)
\(\Leftrightarrow\frac{x}{y}=\frac{5}{4}\)