ta có \(A=\frac{-24}{n}+\frac{17}{n}=\frac{\left(-24\right)+17}{n}=\frac{-7}{n}\)
\(\Rightarrow n\inƯ\left(-7\right)=\left\{-7,-1,1,7\right\}\)
\(\Rightarrow n=-7;n=-1;n=1;n=7\) để A là số nguyên
\(B=\frac{n-8}{n+1}+\frac{n+3}{n+1}=\frac{n-8+n+3}{n+1}=\frac{2n-5}{n+1}=\frac{2n+2-6}{n+1}=2-\frac{7}{n+1}\)
\(\Rightarrow n+1\inƯ\left(7\right)=\left\{-7;-1;1;7\right\}\)
nếu \(n+1=-7\Rightarrow n=-8\)
\(n+1=-1\Rightarrow n=-2\)
\(n+1=1\Rightarrow n=0\)
\(n+1=7\Rightarrow n=6\)
vậy \(n\in\left\{-8;-2;0;6\right\}\)để B là số nguyên
