Question

tìm số tự nhiên x,y biết:

(x-2).(y-1)=0

(x-2).(y+2)=7

(x+1).(2y+1)=12

(2x-1).(2y-3)=1

Answer 1

\(\left(x-2\right).\left(y-1\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x-2=0\\y-1=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=2\\y=1\end{cases}}\)

Vậy \(\orbr{\begin{cases}x=2\\y=1\end{cases}}\)

Ủng hộ nha Nguyen Phuong Thao

Answer 2

1)(x-2)(y-1)=0

=> \(\left[{}\begin{matrix}x-2=0\\y-1=0\end{matrix}\right. \)=>\(\left[{}\begin{matrix}x=2\\y=1\end{matrix}\right.\)

   Vậy x,y\(\in\){2;1}