Question

Tìm số tự nhiên x

1,      2^x = 32

2,     2^x+1 = 32

3,     x³ = 125

4,     ( x + 1 )³ = 125

Answer 1

\(2^x=32=>x=5\)

\(2^{x+1}=32=>x+1=5=>x=4\)

\(x^3=125=>x=5\)

\(\left(x+1\right)^3=125=>x+1=5=>x=4\)

Answer 2

3. x³ = 125 => x = 5

4. (x + 1)³ = 125 

   (x + 1)³ = 5³

=> x + 1 = 5

=> x = 4 

t i c k nhé!! 45457474678789886973463125135153152454654657657868768

Answer 3

a,       

2^x = 32

2^x = 2⁵

=> x = 5

b,       

2^{x + 1} = 32

2^{x + 1} = 2⁵

=> x + 1 = 5

     x       = 5 - 1

     x       = 6

c,

x³ = 125

x³ = 5³

=> x = 5

d, 

( x - 1 )³ = 125

( x - 1 )³ = 5³

=> x - 1 = 5

     x      = 5 + 1 

     x      = 6

Answer 4

3. x³ = 125 => x = 5

4. (x + 1)³ = 125 

   (x + 1)³ = 5³

=> x + 1 = 5

=> x = 4 

 mk nha ^_^

Answer 5

1, Ta có:      2^x = 32

     <=>        2^x = 2⁵

      => x = 5

2,  Ta có:   2^x+1 = 32

     <=>     2^x+1 = 2⁵

       => x + 1 = 5

       => x = 4

3,     x³ = 125

4,     ( x + 1 )³ = 125