Question

tim so tu nhien x biet

a) (x-35)-120=0

b)124+(118-x)=217

c) 156-(x+61)=82

Answer 1

a) \(\left(x-35\right)-120=0\)

\(\Rightarrow x-35=120\)

\(\Rightarrow x=120+35\)

\(\Rightarrow x=155\)

b) \(124+\left(118-x\right)=217\)

\(\Rightarrow118-x=93\)

\(\Rightarrow x=25\)

c) \(156-\left(x+61\right)=82\)

\(\Rightarrow x+61=74\)

\(\Rightarrow x=13\)

Answer 2

a) ( x - 35 ) - 120 =0

x - 35 = 0 + 120

x - 35 = 120

x = 120 + 35

x = 155

b) 124 + ( 118 - x ) = 217

118 - x = 217 - 124

118 - x = 93

x = 118 - 93

x = 25

c) 156 - ( x + 61 ) = 82

x + 61 = 156 - 82

x + 61 = 74

x = 74 - 61

x = 13