12 x ( x - 1 ) = 0
=> x - 1 = 0
x = 0 + 1
x = 1
=> 12x mũ 2 - 12x = 0
=> 12x mũ 2 = 12x
=> Vô lí
12x(x-1) = 0
=> \(\orbr{\begin{cases}12x=0\\x-1=0\end{cases}}\)
=> \(\orbr{\begin{cases}x=0\\x=1\end{cases}}\)
12 .(x - 1) = 0
=> x - 1 = 0 : 12
=> x - 1 = 0
=> x = 0 + 1
=> x = 1
\(12\times\left(x-1\right)=0\)
\(x-1=0:12\)
\(x-1=0\)
\(x=0+1\)
\(x=0\)
