Question

tìm số tư nhiên x 

a,(2600+6400)-3-x=1200

b,[(6.x-72):2-84].28=5628
 

Answer 1

a) x = 7797

                      

Answer 2

a) \(\left(2600+6400\right)-3-x=1200\)

\(\Rightarrow9000-3-x=1200\)

\(\Rightarrow3-x=9000-1200\)

\(\Rightarrow3-x=7800\)

\(\Rightarrow x=7797\)

b) \(\left[\left(6\cdot x-72\right):2-84\right]\cdot28=5628\)

\(\Rightarrow\left[\left(6\cdot x-72\right):2-84\right]=5628:28\)

\(\Rightarrow\left[\left(6\cdot x-72\right):2-84\right]=201\)

\(\Rightarrow\left(6\cdot x-72\right):2=201+84\)

\(\Rightarrow\left(6\cdot x-72\right):2=285\)

Đến dei bạn tự làm, ý b mình không chắc chắn lắm

Answer 3

x=107