\(\frac{16}{2^n}=2\)
=> \(2\cdot2^n=16\)
=> \(2^n=8=2^3\)
=> n = 3
Vậy,........
Ta có: 16 / 2 ^ n = 2
suy ra 2 ^ n = 16 : 2
2 ^ n = 8
2 ^ n = 2 ^ 3
suy ra : n = 3
\(\frac{16}{2^n}=2\)
\(=\frac{16.2^{-n}}{16}=\frac{2}{16}\Rightarrow2^{-n}=8^{-1}\Rightarrow2^{-n}=\left(2^3\right)^{-1}\Rightarrow-n=3\left(-1\right)\Rightarrow-n=-3\)
\(\Rightarrow n=3\)
\(\frac{16}{2^n}=2\)
\(\Rightarrow2.2^n=16\)
\(\Rightarrow2^{1+n}=16\)
\(\Rightarrow2^{1+n}=2^4\)
\(\Rightarrow1+n=4\)
\(\Rightarrow n=4-1\)
\(\Rightarrow n=3\)
Vậy n = 3
_Chúc bạn học tốt_
