tìm STN n đẻ 22n -3 la so nguyen to, n=
tong sau day la so nguyen to hay hop so: 3.5.7 + (2n+1).(2n+3).(2n+5) voi n la so tu nhien
1)n+1 va 3n+4 la nguyen to cung nhau
2)2n+3 va 4n+8 la 2 so nguyen to cung nhau
Tìm so tu nhien n de 22n -3 la so nguyen to. Ket qua là n =
chung to rang hai so n + 1 va 2n + 3 la hai so nguyen to cung nhau
chung to rang 2n + 1 va 2n + 3 ( n\(\in\)N ) la 2 so nguyen to cung nhau
a, tim n de n^2 + 2006 la mot so chinh phuong
b, Cho n la so nguyen to lon hon 3. Hoi n^2 + 2006 la so nguyen to hay hop so.
tìm n thuộc N ,sao cho
a,7 x n la so nguyen to
b,n x {5+4} la so nguyen to
chung to rang voi moi so tu hien n thi 2n+1 va 2n^2 -1 la hai so nguyen to