Answer:
\(\left(3n+2\right)⋮\left(n-1\right)\)
\(\Rightarrow3\left(n-1\right)+5⋮n-1\)
\(\Rightarrow5⋮n-1\)
\(\Rightarrow n-1\inƯ\left(5\right)=\left\{1;5\right\}\)
\(n-1=1\Rightarrow n=2\)
\(\Rightarrow n-1=5\Rightarrow n=6\)
Vậy \(n\in\left\{2;6\right\}\)