Ta có : 4n + 5 chia hết cho 2
\(\Rightarrow\) \(4n+5\inƯ\left(2\right)\)
Mà \(Ư\left(2\right)=\left\{1;2;-1;-2\right\}\)
\(\Rightarrow\) \(4n+5\in\left\{1;2;-1;-2\right\}\)
\(\Rightarrow\) \(4n\in\left\{6;7;4;3\right\}\)
\(\Rightarrow\) \(n\in\left\{\frac{3}{2};\frac{7}{4};1;\frac{3}{4}\right\}\)
Vì \(n\in N\) \(\Rightarrow\) \(n=1\)
ta có :
\(4n+5⋮2\)
\(\Rightarrow4n+2+3⋮2\)
\(\Rightarrow2.\left(n+2\right)+3⋮2\)
mà \(2.\left(n+2\right)⋮2\)
.......
xem lại đề giúp mk