2n + 5 ⋮ n + 1
Vì ( n + 1) ⋮ ( n + 1)
=> 2 ( n + 1 ) ⋮ ( n + 1 )
=> ( 2n + 2) ⋮ ( n + 1 )
=> ( 2n + 5 ) - ( 2n + 2 ) ⋮ ( n + 1 )
=> ( 2n + 5 - 2n - 2 ) ⋮ ( n + 1 )
=> 3 ⋮ ( n + 1 )
=> ( n + 1 ) ∈ Ư(3) = { 1; 3 }
=> n ∈ { 0; 2}
Vậy n ∈{ 0; 2}
Học Tốt <3