\(\dfrac{2x+4}{2x+1}=\dfrac{2x+1+3}{2x+1}=1+\dfrac{3}{2x+1}\Rightarrow2x+1\inƯ\left(3\right)=\left\{\pm1;\pm3\right\}\)
2x+1 | 1 | -1 | 3 | -3 |
x | 0 | -1 | 1 | -2 |
Nguyễn Huy Tú biến đổi sai
\(\frac{x+2}{2x+1}=\frac{2.\left(x+2\right)}{2.\left(2x+1\right)}=\frac{2x+4}{4x+2}\)Chứ