Các câu hỏi tương tự
\(\frac{-150.\left(1352-41\right)}{\left(1352-41\right).\left(150-15\right)}< x< \frac{\left(2400:48\right)-250}{350-\left(3600:12\right)}\)
\(\frac{-150.\left(1352-41\right)}{\left(1352-41\right)\left(150-15\right)}< x< \frac{2400:48-250}{350-3600:12}\)
tìm x thuộc Z
tìm X
\(10.07-\left[3,927-\left(3,63-\frac{3}{20}\right)\right]\le x\le1,5.\left(9,2-\frac{2}{5}\right)+\left(3,2-3,12\right).\left(4\frac{1}{10}-2,35\right)\)
\(\left(x\in Z\right)\)
Rút gọn:
a,\(\frac{15.\left(1352-41\right)}{\left(1352-41\right)\left(150-15\right)}\)
b,\(\frac{2^{10}.6^{15}+3^{14}.15.4^{13}}{2^{18}.18^7.3^3+3^{15}.2^{25}}\)
Tìm x, biết:frac{3}{left(x+2right)left(x+5right)}+frac{5}{left(x+5right)left(x+10right)}+frac{7}{left(x+10right)left(x+17right)}frac{x}{left(x+2right)left(x+17right)}left(xnotin-2;-5;-10;-17right)frac{2}{left(x-1right)left(x-3right)}+frac{5}{left(x-3right)left(x-8right)}+frac{12}{left(x-8right)left(x-20right)}-frac{1}{x-20}-frac{3}{4}Với xnotin1;3;8;20frac{x+1}{10}+frac{2+1}{11}frac{x+1}{12}frac{x+1}{13}+frac{x+1}{14}frac{x-10}{30}+frac{x-14}{43}+frac{x-5}{95}+frac{x-148}{8}0
Đọc tiếp
Tìm x, biết:
\(\frac{3}{\left(x+2\right)\left(x+5\right)}+\frac{5}{\left(x+5\right)\left(x+10\right)}+\frac{7}{\left(x+10\right)\left(x+17\right)}=\frac{x}{\left(x+2\right)\left(x+17\right)}\left(x\notin-2;-5;-10;-17\right)\)
\(\frac{2}{\left(x-1\right)\left(x-3\right)}+\frac{5}{\left(x-3\right)\left(x-8\right)}+\frac{12}{\left(x-8\right)\left(x-20\right)}-\frac{1}{x-20}=-\frac{3}{4}\)
Với \(x\notin1;3;8;20\)
\(\frac{x+1}{10}+\frac{2+1}{11}\frac{x+1}{12}=\frac{x+1}{13}+\frac{x+1}{14}\)
\(\frac{x-10}{30}+\frac{x-14}{43}+\frac{x-5}{95}+\frac{x-148}{8}=0\)
Bài 2 :
a, \(\frac{3}{\left(x+2\right)\left(x+5\right)}+\frac{5}{\left(x+5\right)\left(x+10\right)}+\frac{7}{\left(x+10\right)\left(x+17\right)}=\frac{x}{\left(x+2\right)\left(x+17\right)}\)
b, \(\frac{2}{\left(x-1\right)\left(x-3\right)}+\frac{5}{\left(x-3\right)\left(x-8\right)}+\frac{12}{\left(x-8\right)\left(x-20\right)}-\frac{1}{\left(x-20\right)}=\frac{-3}{4}\)
Câu hỏi : Tìm số nguyên x biết : \(\left(-\frac{2}{3}-\frac{1}{2}\right):-\frac{1}{4}\le x\le\left(-\frac{5}{6}+\frac{2}{\frac{1}{4}}:-\frac{3}{2}\right).\left(-\frac{7}{\frac{1}{2}}\right)\)
Giúp ik
Tìm số nguyên x biết \(\frac{1}{2}-\left(\frac{1}{3}+\frac{1}{4}\right)\le x\le\frac{1}{24}-\left(\frac{1}{8}-\frac{1}{3}\right)\)
Câu 1 Tim số nguyên x, biet rằng4frac{1}{3}.left(frac{1}{6}-frac{1}{2}right)letimeslefrac{2}{3}.left(frac{1}{2}-frac{1}{2}-frac{3}{4}right)Câu 2 : Tính1frac{13}{15}.0,75-left(frac{104}{195}+25%right).frac{24}{47}-3frac{12}{13}:3Câu 3 ; Tìm x Bietleft(frac{1}{12}+3frac{1}{6}-30,75right).times-8left(frac{3}{5}+0,415+frac{1}{200}right):0,01Câu 4 : So Sánh Afrac{10^8+2}{10^8-1};
Đọc tiếp
Câu 1 Tim số nguyên x, biet rằng
\(4\frac{1}{3}.\left(\frac{1}{6}-\frac{1}{2}\right)\le\times\le\frac{2}{3}.\left(\frac{1}{2}-\frac{1}{2}-\frac{3}{4}\right)\)
Câu 2 : Tính
\(1\frac{13}{15}.0,75-\left(\frac{104}{195}+25\%\right).\frac{24}{47}-3\frac{12}{13}:3\)
Câu 3 ; Tìm x Biet
\(\left(\frac{1}{12}+3\frac{1}{6}-30,75\right).\times-8=\left(\frac{3}{5}+0,415+\frac{1}{200}\right):0,01\)
Câu 4 : So Sánh \(A=\frac{10^8+2}{10^8-1}\);