\(a,3+x=5\)
\(x=5-3\)
\(x=2\)
\(b,x-7=0\)
\(x=7\)
\(c,7+x=1\)
\(x=1-7\)
\(x=-6\)
Câu 2 : Ta có : \(30=2.3.5\)
\(45=3^2.5\)
\(135=3^3.5\)
Vậy \(ƯCLN\left(30;45;135\right)=3.5=15\)
\(\RightarrowƯC\left(30;45;135\right)=\left\{1;2;3;5\right\}\)
x+3=5
<=> x=5-3
<=> x=2
b,x-7=0
<=> x=0+7
<=> x=7
c,7+x=1
<=> x=1-7
<=> x=(-6)