Ta có: 4-(27-3) = x-(13-4)
4-24 = x-11
x-11 =-20
x =-19
Vậy: x = -19
Ta có: 4-(27-3) = x-(13-4)
4-24 = x-11
x-11 =-20
x =-19
Vậy: x = -19
Đúng nha\(4-\left(27-3\right)=x-\left(13-4\right)\)
\(4-24=x-9\)
\(-20=x-9\)
\(x=-20+9\)
\(x=-11\)
Ta có: 4-(27-3) = x-(13-4)
4-24 = x-11
x-11 =-20
x =-19
Vậy: x = -19
Ta có: 4-(27-3) = x-(13-4)
4-24 = x-11
x-11 =-20
x =-19
Vậy: x = -19
Đúng nha\(4-\left(27-3\right)=x-\left(13-4\right)\)
\(4-24=x-9\)
\(-20=x-9\)
\(x=-20+9\)
\(x=-11\)
bài 1: tìm số nguyên x, biết
a) \(\left(25-2x\right)^3\): 5 - \(3^2\)= \(4^2\) b) 2 x \(3^x\)= \(10\) x \(3^{12}\) + 8 x \(27^4\)
Tìm số tự nhiên x , biết
\(2\cdot\left(x-1\right)^2=8\)
\(\left(2x+1\right)^3=125\)
\(\left(x-2\right)^5=243\)
\(5\left(x-4\right)^2-7=13\)
\(221-\left(3x+2\right)^3=96\)
\(\frac{\left(27\frac{5}{19}-26\frac{4}{13}\right)\left(\frac{3}{4}+\frac{19}{59}-\frac{3}{18}\right)}{\left(\frac{3}{4}+x\right).\frac{27}{33}}=\frac{\frac{1}{13.36}+\frac{1}{14.17}}{\frac{1}{13.15}+\frac{1}{14.16}+\frac{1}{15.17}}\)
Tìm x
Tìm x:
\(\frac{\left(27\frac{5}{19}-26\frac{4}{13}\right)\left(\frac{3}{4}+\frac{15}{59}-\frac{3}{118}\right)}{\left(\frac{3}{4}+x\right)\frac{27}{33}}=\frac{\frac{1}{13.16}+\frac{1}{14.17}}{\frac{1}{13.15}+\frac{1}{14.16}+\frac{1}{15.17}}\)
1.Tìm số nguyên x
a)-2(x+6)=8-6(x-10)
b)\(-4\left(2x+9\right)=\left(x+13\right)+\left(-8x+3\right)\)
Tìm các số nguyên x, y, z, t biết: \(\frac{27}{4}\)=\(\frac{-x}{3}\)=\(\frac{3}{y^2}\)=\(\frac{\left(z+3\right)^3}{-4}\)=\(\frac{\left|t\right|-2}{8}\)
Tìm số nguyên \(x\) biết:
a) \(\left|x-3\right|-\left(-3\right)=4\)
b) \(x-\left(1-x\right)=5+\left(-1+x\right)\)
Tìm x, biết :
\(\frac{7}{\left(x+3\right)\left(x+10\right)}+\frac{3}{\left(x-4\right)\left(x-7\right)}+\frac{6}{\left(x-7\right)\left(x-13\right)}\)
\(+\frac{15}{\left(x-13\right)\left(x-28\right)}-\frac{1}{x-28}=\frac{-1}{20}\)
giúp mình với các bạn !!!!!!!!!!!!
Tìm các số nguyên x thỏa mãn :
\(\left(x-\dfrac{1}{2}\right).\left(x+\dfrac{3}{4}\right)\le0\)