\(\left(x+1\right)\left(xy-5\right)=5\)
\(\Rightarrow\left(x+1\right);\left(xy-5\right)\inƯ\left(5\right)=\left\{\pm1;\pm5\right\}\)
Xét bảng
x+1 | 1 | -1 | 5 | -5 |
xy-5 | 5 | -5 | 1 | -1 |
x | loại | -2 | 4 | -6 |
y | loại | 0 | 6/4 | -4/6 |
Vậy........................
P/S: ko chắc
\(\left(x+1\right)\left(xy-5\right)=5\)
\(\Rightarrow\left(x+1\right);\left(xy-5\right)\inƯ\left(5\right)=\left\{\pm1;\pm5\right\}\)
Xét bảng
x+1 | 1 | -1 | 5 | -5 |
xy-5 | 5 | -5 | 1 | -1 |
x | loại | -2 | 4 | -6 |
y | loại | 0 | 6/4 | -4/6 |
Vậy........................
P/S: ko chắc
tim cap so nguyen x;y biet (x-1).(xy+2)=5
tim so nguyen x,y biet:
a)(x+2)(y-3)=5
b)(x+1)(xy-1)=3
a) tim so nguyen x sao cho : 4x+5 chia het cho 2x-1
b) tim so nguyen x va y biet : xy+3x-2y -11 = 0
giup mik nha ! ai nhanh nhat mik tick cho !
Bai 1 : Tim cac so nguyen x , y biet :
a, xy - 2x -3y = 5
b, xy - 2x + 5y = 2
Tim so nguyen x,y biet
(x+1)^2+(y-1)^2=0
(x+3)×(y+1)=3
xy-2x=5
Bai 1 : Tim cac so nguyen x , y biet :
a, x +xy + y = 9
b, xy - 2x -3y = 5
c, xy - 2x + 5y = 2
tim cac so nguyen x , y biet
e) (x - 3) (x + y)=-11
f)xy + 3x - 2y - 6 = 5
tim so nguyen x,y biet
x(xy+2)+y=1
tim cac so xy nguyen duong biet /x-2y+1/*/x+4y+3/=20