(x-5)-7=x-1-(x-2)
x-5-7=x-1-x+2
x-12=1
x=13
\(\left(x-5\right)-7=x-1-\left(x-2\right)\)
\(x-5-7=x-1-x+2\)
\(x+2=1\)
\(x=-1\)
x-5-7=x-1-x+2
x-12-1=0
x-13=0
x=13
a, \(\left(x-5\right)-7=x-1-\left(x-2\right)\)
\(\Leftrightarrow x-5-7=x-1-x+2\)
\(\Leftrightarrow x-12-1=0\)
\(\Leftrightarrow x-12=1\)
\(\Leftrightarrow x=13\)
a) ( x - 5 ) -7 = x - 1 - (x-2 )
<=>x - 5 - 7 = x - 1 - x + 2
<=> x - 12 - 1 = 0
<=> x -13 = 0
<=> x = 0 + 13
<=> x = 13
Vậy x = 13