\(35-\left|2x-1\right|=14\)
\(\Leftrightarrow\left|2x-1\right|=21\)
\(\Leftrightarrow\orbr{\begin{cases}2x-1=21\left(x\ge\frac{1}{2}\right)\\2x-1=-21\left(x< \frac{1}{2}\right)\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}2x=22\\2x=-20\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=11\left(TM\right)\\x=-10\left(TM\right)\end{cases}}\)
\(35-|2x-1|=14\)
\(|2x-1|=21\)
\(\Rightarrow\orbr{\begin{cases}2x-1=21\\2x-1=-21\end{cases}\Rightarrow\orbr{\begin{cases}2x=22\\2x=-20\end{cases}\Rightarrow}\orbr{\begin{cases}x=11\\x=-10\end{cases}}}\)
Ta có:[2x-1]=35-14
=>[2x-1]=21
=>2x=21+1
=>2x=22
=>x=22/2
=>x=11
35-|2x-1|=14
|2x-1|=35-14
|2x-1|=21
* 2x-1=21 * 2x-1=-21
2x=21+1 2x=-21+1
2x=22 2x=-20
x=22:2 x=-20:2
x=11 x=-10
Vậy x=11 hoặc x=-10
Trl:
\(35-\left|2x-1\right|=14\)
\(\Rightarrow\left|2x-1\right|=35-14\)
\(\Rightarrow\left|2x-1\right|=21\)
Có 2 TH sau :
2x - 1 = 21 hoặc 2x - 1 = - 21
2x = 21 + 1 hoặc 2x = -21 + 1
2x = 22 hoặc 2x = -20
x = 11 hoặc x = -10
Vậy \(x\in\left\{11;-10\right\}\)
35-|2x-1|=14
|2x-1|=35-14=21
=>2x-1=21, -21
TH1: 2x-1=21
2x=21+1=22
x=22:2=11
TH2: 2x-1=-21
2x=-21+1=-20
x=-20:2=-10
Vay x=11, -10