Ta có : \(n^{150}< 5^{225}\)
\(\Rightarrow\left(n^2\right)^{75}< \left(5^3\right)^{75}\)
=> n2 < 125
=> n2 = {1;4;9;16;25;36;49;64;81;100}
=> n = {1;2;3;4;5;6;7;8;9;10}
Vì n là lớn nhất
Nên n = 10
Vậy n = 10
ta có:
\(n^{150}=\left(n^6\right)^{25};5^{225}=\left(5^9\right)^{25}\)
\(\Rightarrow n^6< 5^9\)
\(max\left(n\right)=11\)