Question

Tìm số dư trong phép chia   3²⁰⁰³ cho 13

Answer 1

3³ = 27 = 1 (mod 13)

=> (3³)⁶⁶⁷ = 1⁶⁶⁷  (mod 13)

=> 3²⁰⁰¹ = 1 (mod 13) 

=> 3²⁰⁰¹.3² = 1.3² (mod 13)

=> 3²⁰⁰³ = 9 (mod 13)

Answer 2

bài làm

3³ = 27 = 1 (mod 13)

=> (3³)⁶⁶⁷ = 1⁶⁶⁷  (mod 13)

=> 3²⁰⁰¹ = 1 (mod 13) 

=> 3²⁰⁰¹.3² = 1.3² (mod 13)

=> 3²⁰⁰³ = 9 (mod 13)

vậy ....................

hok tốt

Answer 3

3^3 = 27 = 1 (mod 13)

 

=> (3^3)^667 = 1^667 (mod 13)

 

=> 3^2001 = 1 (mod 13) 

 

=> 3^2001.3^2 = 1.3^2 (mod 13)

 

=> 3^2003 = 9 (mod 13)

Vậy 3^2003 : 13 dư 9