Ta cá:2x+2y=2(x+y)
TH1:x+y chẵn ta cá:
Vi x+y chẵn nên x+y chia hết cho 2
\(\Rightarrow x+y=2k\)
\(\Rightarrow2\left(x+y\right)=2\times2\times k=4k⋮4\)
\(\Rightarrow2\left(x+y\right)⋮4\)
\(\Rightarrow2x+2y⋮4\)
Suy ra 2x+2y:4 dư 0
TH2:x+y lẻ
Vi x+y lẻ nen x+y :2 dư 1
\(\Rightarrow x+y=2h+1\)
\(\Rightarrow2\left(x+y\right)=2\left(2h+1\right)=2\times2\times h+2\times1\)
=4h+2:4 dư 2
Suy ra 2(x+y):4 dư 2
Suy ra 2x +2y:4 dư 2
Vậy 2x+2y:4 dư 0 hoặc 2